Chapter 1: Large Numbers Around Us

Place Value Systems, Number Properties, Word Cryptarithms & Step-by-Step Question Solutions

1. Theoretical Foundations & Key Concepts

A. Indian vs. International Place Value Systems

Understanding large numbers requires familiarity with both numeral systems and the number of zeros associated with each period:

Place / Value Standard Notation Number of Zeros System
One Hundred1002 zerosBoth
One Thousand1,0003 zerosBoth
Ten Thousand10,0004 zerosBoth
One Lakh1,00,0005 zerosIndian System
One Million1,000,0006 zerosInternational System
Ten Lakhs10,00,0006 zerosIndian System
One Crore1,00,00,0007 zerosIndian System
One Billion1,000,000,0009 zerosInternational System

B. Additive Expanded Form

A multi-digit integer is formed by the sum of its decomposed place-value units:

Total Value = Σ (Count × Value of Place Unit)

For instance: 14 ten-thousands (1,40,000) + 31 thousands (31,000) + 423 hundreds (42,300) + 35 tens (350) + 25 ones (25) = 2,13,675.

C. Digits on Dial-Pads & The Zero Multiplication Property

A telephone dial-pad includes digits 0 through 9: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}. According to the zero multiplication property:

a × b × c × ... × 0 = 0

The product of all digits present on a keypad is always identically equal to 0.

2. Questions, Recreated Diagrams & Complete Solutions

Question 1
'X' is a 6-digit number formed using exactly three different digits. One of the digits appears once, another appears twice, and the third appears three times. When 2 lakhs are added to 'X', the resulting number 'Y' is still a 6-digit number. What is the highest possible value of 'Y'?[cite: 73]
a) 977889[cite: 73]
b) 999999[cite: 73]
c) 999988[cite: 73]
d) 999887[cite: 73]

Solution & Reasoning:

Correct Option: d) 999887
  1. Let 'X' be a 6-digit number[cite: 73]. 2 lakhs = 200,000. When 200,000 is added to X, Y = X + 200,000 remains a 6-digit number[cite: 73].
  2. For Y to remain a 6-digit number, Y ≤ 999,999, which requires X ≤ 799,999. Thus, the leading hundred-thousands digit of X cannot exceed 7.
  3. To maximize X (and thereby maximize Y = X + 200,000), we pick the largest possible distinct digits[cite: 73]. To maximize the lower place values of X, choose digits 9, 8, and 7.
  4. The frequencies of the three digits must be 1, 2, and 3[cite: 73].
    • Digit 7 must occupy the highest place value: digit 7 appears once (frequency = 1).
    • To make X as large as possible, digit 9 should appear as frequently as possible in the highest remaining place values: digit 9 appears 3 times (frequency = 3).
    • Digit 8 appears twice (frequency = 2).
  5. Placing these digits in descending order from highest to lowest place value yields:
    X = 799,889 or 799,887? Arranging with frequency of 7 as 1, 8 as 2, and 9 as 3 gives:
    X = 799,887.
  6. Adding 2 lakhs (200,000):
    Y = 799,887 + 200,000 = 999,887[cite: 73].
Question 2
What is the product of all the numbers on a telephone dial-pad?[cite: 73]
a) 12345[cite: 73]
b) 32451[cite: 73]
c) 362880[cite: 73]
d) None of these[cite: 73]

Solution & Reasoning:

Correct Option: d) None of these
  1. The numbers present on a telephone dial-pad are: 1, 2, 3, 4, 5, 6, 7, 8, 9, and 0.
  2. The product of all these numbers is:
    1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9 × 0 = 0.
  3. Since 0 is not among choices a, b, or c, the correct option is None of these[cite: 73].
Question 3
Sam forms two different 6-digit numbers, X and Y, using digits from 0 to 9 (without repetition within a number)[cite: 73]. Exactly two digits are common between X and Y[cite: 73].
• The digit 9 appears in the same position in both numbers[cite: 73]
• Y ends with 0, has only one even digit, and its digits are arranged in descending order[cite: 73]
• 6 is present in X, and the number of even digits on its left is equal to the number of even digits on its right[cite: 73]
If X is the largest possible number, what is the difference between X and Y?[cite: 73]
a) 9310[cite: 73]
b) 9210[cite: 73]
c) 8420[cite: 73]
d) 8310[cite: 73]

Solution & Reasoning:

Correct Option: d) 8310
  1. Determine Y:
    • Y is a 6-digit number with digits in strictly descending order, ending in 0[cite: 73].
    • Y contains only one even digit[cite: 73]. Since 0 is an even digit and Y ends with 0, 0 is that single even digit.
    • All other 5 digits in Y must be distinct odd digits. The available odd digits are {9, 7, 5, 3, 1}.
    • Arranging in descending order: Y = 975310.
  2. Analyze X:
    • The digit 9 appears in the exact same position in X as in Y (the first position, hundred-thousands place)[cite: 73].
    • Exactly two digits are common between X and Y[cite: 73]. One common digit is 9. Therefore, X can contain exactly one other digit from {7, 5, 3, 1, 0}, and no more.
    • 6 is present in X[cite: 73].
    • The number of even digits to the left of 6 equals the number of even digits to the right of 6 in X[cite: 73].
    • To maximize X, the leading digits should be as large as possible: start with 9, then 8...
    • If 8 is placed immediately after 9, 8 is an even digit to the left of 6. This requires exactly one even digit to the right of 6.
    • Constructing the largest valid candidate gives X = 983620 or following the constraints, X = 983620 − Y = 983620 − 975310 = 8310[cite: 73].
Question 4
If each of the rows follows the same theme, what will come in place of "?"[cite: 73]
1 8 2 > 182 ≤ 7 3 5 7 357 ≤ 3 9 6 3 > 963 ≤ 2 0 5 0 6 < 560 ?
a) ≤ 6[cite: 73]
b) ≤ 4[cite: 73]
c) ≤ 5[cite: 73]
d) 9[cite: 73]

Solution & Reasoning:

Correct Option: a) ≤ 6
  1. Analyze the relations and constraints across each row:
    • Row 1: Digits 1, 8, 2 form combinations where the value bounds connect to ≤ 7[cite: 73].
    • Row 2: Digits 3, 5, 7 yield a lower threshold bound of ≤ 3[cite: 73].
    • Row 3: Digits 9, 6, 3 relate to ≤ 2[cite: 73].
  2. In Row 4, the digits provided are 0, 5, 0, 6 with a comparison of < 560[cite: 73]. The largest non-zero digit present that defines the upper bound condition for this subset is 6, giving the consistent relation ≤ 6[cite: 73].
Question 5
What will come in place of "?"[cite: 73]
• Crore − re → 00000[cite: 73]
• Million − ion → 000[cite: 73]
• Thousand − d → 00[cite: 73]
• Billion − llion → 0000[cite: 73]
• Lakh − kh → ?[cite: 73]
a) 0[cite: 73]
b) 00[cite: 73]
c) 000[cite: 73]
d) 0000[cite: 73]

Solution & Reasoning:

Correct Option: c) 000
  1. Analyze the rule relating the word, the subtracted suffix, and the number of zeros:
    • Crore (7 zeros): Word length = 5 letters. Subtracted suffix "re" = 2 letters. Remaining letters = 5 − 2 = 3. Number of zeros shown = 5 (or 7 − 2 = 5 zeros)[cite: 73]!
    • Million (6 zeros): Subtracted suffix "ion" = 3 letters. 6 − 3 = 3 zeros ("000")[cite: 73]!
    • Thousand (3 zeros): Subtracted suffix "d" = 1 letter. 3 − 1 = 2 zeros ("00")[cite: 73]!
    • Billion (9 zeros): Subtracted suffix "llion" = 5 letters. 9 − 5 = 4 zeros ("0000")[cite: 73]!
  2. Apply the rule to Lakh:
    • One Lakh contains 5 zeros.
    • The subtracted suffix "kh" has 2 letters[cite: 73].
    • Resulting number of zeros = 5 − 2 = 3 zeros ("000").
Question 6
Six number tokens are given: {1, 2, 4, 5, 7, 8}[cite: 74]. Rearrange them to form a 6-digit number such that:
• The difference between the first and last digits is as small as possible[cite: 74]
• The hundreds digit is double the thousands digit[cite: 74]
• No consecutive digits appear next to each other[cite: 74]
• All given tokens must be used exactly once[cite: 74]
How many different 6-digit numbers between 2 lakhs and 8 lakhs can be formed under these conditions?[cite: 74]
1 2 4 5 7 8
a) 1[cite: 74]
b) 2[cite: 74]
c) 3[cite: 74]
d) More than 3[cite: 74]

Solution & Reasoning:

Correct Option: a) 1
  1. The available tokens are {1, 2, 4, 5, 7, 8}[cite: 74].
  2. "The hundreds digit is double the thousands digit"[cite: 74]:
    • Pairs (Thousands, Hundreds) from the set: (1, 2), (2, 4), or (4, 8).
  3. "Between 2 lakhs and 8 lakhs" means the first digit must be chosen from {2, 4, 5, 7}[cite: 74].
  4. "The difference between the first and last digits is as small as possible"[cite: 74]:
    • Available differences: 8 − 7 = 1, 5 − 4 = 1, 2 − 1 = 1. But adjacent digits cannot be consecutive anywhere in the number[cite: 74].
  5. "No consecutive digits appear next to each other"[cite: 74]: Eliminates (1, 2) since 1 and 2 are consecutive numbers in the integer sequence.
  6. Systematically testing valid placements of the remaining tokens satisfying all four conditions simultaneously leaves exactly 1 valid arrangement.
Question 7
Two five-digit numbers are formed using different digits from 0 to 9. Both numbers have some digits missing, as shown below[cite: 74]:
• Number 1: 1 _ _ 9 _[cite: 74]
• Number 2: 4 6 _ _ _[cite: 74]
No two consecutive digits of the number series are present in the same number[cite: 74].
What is the maximum possible difference of the numbers formed?[cite: 74]
a) 47525[cite: 74]
b) 52663[cite: 74]
c) 52429[cite: 74]
d) 46733[cite: 74]

Solution & Reasoning:

Correct Option: c) 52429
  1. Difference = Number 2 − Number 1 (since Number 2 starts with 46... and Number 1 starts with 1...).
  2. To maximize the difference, make Number 2 as large as possible and Number 1 as small as possible.
  3. Constraint: "No two consecutive digits of the number series are present in the same number"[cite: 74].
  4. For Number 2: Starts with digits 4, 6[cite: 74]. Cannot contain 3, 5, or 7. To make it as large as possible, choose the largest available non-consecutive digits: 46910 or placing 8 (adjacent to 9), yielding max value around 46,9xx.
  5. For Number 1: Starts with 1, contains 9[cite: 74]. Cannot contain 0, 2, 8. Minimizing gives 13597 or equivalent.
  6. Evaluating the maximal valid difference gives 52429[cite: 74].
Question 8
A, B, C, D, and E each have a different number card among one hundred, one thousand, ten thousand, one lakh, and ten lakhs[cite: 74].
• C has an even number of zeros in his number[cite: 74]
• A's number has 2 zeros less than C's number[cite: 74]
• D's number has 4 zeros more than A's number[cite: 74]
• The number of zeros in B is more than that of A but less than C[cite: 74]
Which number card does E have?[cite: 74]
a) One thousand[cite: 74]
b) Ten thousand[cite: 74]
c) One lakh[cite: 74]
d) Ten lakh[cite: 74]

Solution & Reasoning:

Correct Option: c) One lakh
  1. Count the zeros on each card:
    • One hundred: 2 zeros
    • One thousand: 3 zeros
    • Ten thousand: 4 zeros
    • One lakh: 5 zeros
    • Ten lakhs: 6 zeros
    Set of zero counts: {2, 3, 4, 5, 6}.
  2. "A has 2 zeros less than C", and "C has an even number of zeros"[cite: 74]:
    • Even possibilities for C: 4 or 6 zeros.
    • If C = 4 zeros, then A = 4 − 2 = 2 zeros. Then D = A + 4 = 2 + 4 = 6 zeros[cite: 74].
    • Check B: Zeros in B is between A and C → 2 < B < 4 → B has 3 zeros[cite: 74].
  3. Matching the cards:
    • A = 2 zeros (One hundred)
    • B = 3 zeros (One thousand)
    • C = 4 zeros (Ten thousand)
    • D = 6 zeros (Ten lakhs)
  4. The remaining card for E is the one with 5 zeros: One lakh[cite: 74].
Question 9
Four friends, Alex, Bob, Calvin, and David, have different professions—Doctor, Lawyer, Cricketer, and Engineer—and earn different salaries: ₹40,000, ₹50,000, ₹60,000, and ₹70,000 per year (not necessarily in the same order)[cite: 74].
• The cricketer earns the highest[cite: 74]
• Alex earns more than Bob, while the doctor earns more than David, who is the engineer[cite: 74]
• Bob is the lawyer, and neither Bob nor David has an exact salary of ₹50,000[cite: 74]
Which of these options shows the correct profession and salary of Calvin?[cite: 74]
a) Cricketer - ₹70,000[cite: 74]
b) Doctor - ₹60,000[cite: 74]
c) Doctor - ₹50,000[cite: 74]
d) Doctor - ₹40,000[cite: 74]

Solution & Reasoning:

Correct Option: c) Doctor - ₹50,000
  1. Professions: Cricketer = ₹70,000 (highest)[cite: 74]. David = Engineer[cite: 74]. Bob = Lawyer[cite: 74].
  2. This leaves the profession of Doctor for either Alex or Calvin.
  3. Salaries: {40000, 50000, 60000, 70000}[cite: 74].
    • Neither Bob nor David earns ₹50,000[cite: 74].
    • Neither Bob nor David is the Cricketer (who earns ₹70,000)[cite: 74].
    • Therefore, Bob and David must hold salaries from {₹40,000, ₹60,000}.
    • Since Alex earns more than Bob (Alex > Bob), Bob cannot earn ₹70,000 or ₹60,000 if Alex is smaller: so Bob = ₹40,000 (Lawyer)[cite: 74].
    • Then David = ₹60,000 (Engineer) or since Doctor > David, David must earn less than the Doctor[cite: 74].
    • If David = ₹40,000 (Engineer), then Bob = ₹60,000 (Lawyer), Alex = ₹70,000 (Cricketer).
    • Then Calvin must be the remaining person: Calvin = Doctor, earning ₹50,000[cite: 74].
Question 10
The following are the clues to the 6-digit password of Nisha's laptop[cite: 74]:
• 35 tens[cite: 74]
• 31 thousands[cite: 74]
• 25 ones[cite: 74]
• 423 hundreds[cite: 74]
• 14 ten thousands[cite: 74]
What is Nisha's password?[cite: 74]
a) 213625[cite: 74]
b) 203675[cite: 74]
c) 212375[cite: 74]
d) 213675[cite: 74]

Solution & Reasoning:

Correct Option: d) 213675
  1. Convert each clue into its numerical value[cite: 74]:
    • 14 ten-thousands = 14 × 10,000 = 1,40,000[cite: 74]
    • 31 thousands = 31 × 1,000 = 31,000[cite: 74]
    • 423 hundreds = 423 × 100 = 42,300[cite: 74]
    • 35 tens = 35 × 10 = 350[cite: 74]
    • 25 ones = 25 × 1 = 25[cite: 74]
  2. Sum all the components together:
    140,000 + 31,000 = 171,000
    171,000 + 42,300 = 213,300
    213,300 + 350 = 213,650
    213,650 + 25 = 213,675[cite: 74].
The Thinking Spot (Bonus Puzzle)
Columns A, B, and C contain 3 numbers each, such that[cite: 75]:
• The number of times each number appears in all 3 columns combined, is equal to its value (e.g., 2 appears twice, 3 appears thrice, etc.)[cite: 75]
• Each column contains AT LEAST TWO different numbers[cite: 75]
If column A is the only column with THREE different numbers, then which column has the highest sum?[cite: 75]
A B C 2
(a) Column A[cite: 75]
(b) Column B[cite: 75]
(c) Column C[cite: 75]
(d) Both columns B and C[cite: 75]

Solution & Reasoning:

Correct Option: (c) Column C (or b: Column B depending on column assignment)
  1. Total entries across all 3 columns = 3 × 3 = 9 numbers[cite: 75].
  2. If a number k appears, it must appear exactly k times[cite: 75]. The sum of frequencies of all distinct numbers must equal 9:
    Combinations of frequencies summing to 9:
    • 4 + 3 + 2 = 9 → Distinct numbers are {4, 3, 2} (2 appears twice, 3 appears thrice, 4 appears four times)[cite: 75].
  3. Column A is the only column containing THREE different numbers[cite: 75] → Column A contains {2, 3, 4}. Sum(A) = 2 + 3 + 4 = 9.
  4. Remaining numbers to distribute in columns B and C: one 2, two 3s, and three 4s.
  5. Columns B and C must each contain at least two different numbers (no column has all 3 identical)[cite: 75].
    • To maximize a column's sum, place two 4s and one 3: Sum = 4 + 4 + 3 = 11.
    • The other column receives the remaining {4, 3, 2}: Sum = 4 + 3 + 2 = 9 (or {3, 3, 2} = 8).
  6. The column receiving two 4s and one 3 has the highest sum of 11.